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barxatty [35]
3 years ago
12

Volume and surface area of cylinders

Mathematics
1 answer:
Ghella [55]3 years ago
8 0

Answer:72 pie cubic units

Step-by-step explanation:

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Without overlapping, how many college basketball courts 94ft x 50ft would fit into a football field 360ft x 160ft?
Volgvan
Area of basketball court: 94 x 50 = 4700 square feet

area of football field: 360 x 160 = 57600 square feet

57600 / 4700 = 12.26

so 12 basketball courts 
7 0
2 years ago
Brainliest if your correct
loris [4]

Answer:

it would be the last option

Step-by-step explanation:

4 0
2 years ago
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ZEFG and ZGFH are a linear pair, mZEFG = 3n+ 21, and mZGFH = 2n + 34. What are mZEFG and mZGFH?
marysya [2.9K]

Answer:

The answer is below

Step-by-step explanation:

∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?

Solution:

Two angles are said to form a linear pair if they share a base. Linear pair angles are adjacent angles formed along a line as a result of the intersection of two lines. Linear pairs are always supplementary (that is they add up to 180°).

m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:

m∠EFG + m∠GFH = 180°

3n + 21 + (2n + 34) = 180

3n + 2n + 21 + 34 = 180

5n + 55 = 180

5n = 125

n = 25

Therefore, m∠EFG = 3(25) + 21 = 96°, m∠GFH = 2(25) + 34 = 84°

7 0
2 years ago
The volume of a right cylinder is V = πr2h. If we have an oblique cylinder, like in the figure, what is the volume of a cross-se
olchik [2.2K]
Since you did not attach any picture we cannot say for sure what is the correct answer, but we can discuss the options in order to find the most probable correct answer.

First of all, according to the Cavalieri's principle, an oblique cylinder has the same volume as a right cylinder with the same base surface area and same height.
A cross-section of an oblique cylinder will be a small right cylinder with the same base surface area and a height as small as possible.

I guess the oblique cylinder has height h and it is divided into many (probably 10) cross-sections.

Option A: <span>πr2h
This is exactly the volume of the right cylinder, therefore, unless you are given a cross-section of height h (which would be too easy), this won't be the correct answer.

Option B: </span><span>4πr2h
This is 4 times the right cylinder. Again, here the height of the cross-section should</span> be 4h, but it doesn't sound like a possible data (too easy again).

Option C: <span>1 10 πr2h
Here comes a n issue with the notation: I think the right number you meant to write is (1/10)</span>·πr2h and not 110·<span>πr2h.
If I am right, this means that your oblique cylinder of height h is divided into 10 cross-sections, and therefore the volume of each of these cross-sections will be a tenth of the volume of the oblique cylinder, which means </span>1/10·<span>πr2h.

Option D: </span><span>1 2 πr2h
Here, we have the same notation issue as before. I think you meant (1/2)</span>·<span>πr2h.
Here, your oblique cylinder height h should be divided into only 2 cross-sections. Now, we said the cross-section's height should be the smallest as possible, so an oblique cylinder divided only into two pieces doesn't sound good.

Therefore, the most probable correct answer will be C) </span>(1/10)·<span>πr2h</span>
8 0
3 years ago
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After 2 years, Deion earned $270 in simple interest from a CD into which he initially deposited $6000. What was the annual inter
shusha [124]
I=prt
When I want to find the rate
r=I/pt so
R=(270/6000*2)*100==2.25%
6 0
3 years ago
Read 2 more answers
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