3 years ago

Over which interval(s) is the function decreasing? Please help me I will thank you and give you five stars ⭐️

1 answer:

4 0

There’s no picture so I can’t help you I’m sorry :(

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mr Goodwill [35]

Answer:

y = 8x

Step-by-step explanation:

hope this is what u need if not comment and I'll change it

7 0

2 years ago

zvonat [6]

Answer: $k= \frac{1+\sqrt{321} }{8} , \frac{1-\sqrt{321} }{8}$

Step-by-step explanation:

Move all terms to one side.

$4^{2} -20-k=0$

Use the Quadratic Formula.

$k=\frac{1+\sqrt{321} }{8}$ , $k=\frac{1-\sqrt{321} }{8}$

5 0

2 years ago

neonofarm [45]

Answer:

$(2 {x}^{3} - 5 {x}^{2} + 8)(x + 3) \\ = (2 {x}^{4} - 5 {x}^{3} + 8x + 6 {x}^{3} - 15 {x}^{2} + 24) \\ = 2 {x}^{4} + {x}^{3} - 15 {x}^{2} + 8x + 24$

8 0

2 years ago

Levart [38]

(9y+y) + (6+3)
The answer is 10y+9

5 0

2 years ago

klio [65]

4x + 9 = 2x - 1
4x - 2x = -1 - 9
2x = -10
x = -10/2
x = -5 <===

8 0

2 years ago