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blondinia [14]
3 years ago
6

Patty is building a rope ladder for a tree house. She needs two 5 foot pieces of rope for the sides of the ladder. She needs 7 p

ieces of rope, each 18 inches long, for the steps. How many feet of top does patty need to make the ladder

Mathematics
1 answer:
BigorU [14]3 years ago
6 0

Answer:

  20 1/2 feet

Step-by-step explanation:

The total length is found by adding the lengths of the individual pieces. It can be easier if you use multiplication in place of repeated addition. You want ...

  (2 × 5 feet) + (7 × 18 inches)

At some point in the process, you need to convert inches to feet. This is done by remembering that 12 inches = 1 foot. Dividing inches by 12 gives feet.

The above expression evaluates to

  10 feet + 126 inches = 10 feet + (126/12) feet = 10 feet + 10.5 feet

  = 20.5 feet

_____

A Google search box is a capable units converter and calculator.

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Claudia is reading a book that has 360 pages. she read some of the book last week. she plans to read 46 pages. when she does, sh
gladu [14]
She read 242 pages. I got that by finding what (4/5) x (360) was which is 288 and then subtracted 46 to see what was left over which is 242
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Which term refers to slope <br>​
Andrews [41]

Answer:

slope intercept form

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Solve for b.<br> 7<br> b<br> 12<br> b= ✓ [?]<br> Pythagorean Theorem: a2 + b2 = c2<br> Enter
fomenos

Answer: b=\sqrt{95}

Step-by-step explanation:

To solve for b, we want to use the Pythagorean Theorem as given.

b and 7 are the legs, and 12 is the hypotenuse.

7^2+b^2=12^2      [exponent]

49+b^2=144     [subtract both sides by 49]

b^2=95               [square root both sides]

b=\sqrt{95}

Now we know b=\sqrt{95}.

6 0
2 years ago
Show that the line integral is independent of path by finding a function f such that ?f = f. c 2xe?ydx (2y ? x2e?ydy, c is any p
Juli2301 [7.4K]
I'm reading this as

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy

with \nabla f=(2xe^{-y},2y-x^2e^{-y}).

The value of the integral will be independent of the path if we can find a function f(x,y) that satisfies the gradient equation above.

You have

\begin{cases}\dfrac{\partial f}{\partial x}=2xe^{-y}\\\\\dfrac{\partial f}{\partial y}=2y-x^2e^{-y}\end{cases}

Integrate \dfrac{\partial f}{\partial x} with respect to x. You get

\displaystyle\int\dfrac{\partial f}{\partial x}\,\mathrm dx=\int2xe^{-y}\,\mathrm dx
f=x^2e^{-y}+g(y)

Differentiate with respect to y. You get

\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]
2y-x^2e^{-y}=-x^2e^{-y}+g'(y)
2y=g'(y)

Integrate both sides with respect to y to arrive at

\displaystyle\int2y\,\mathrm dy=\int g'(y)\,\mathrm dy
y^2=g(y)+C
g(y)=y^2+C

So you have

f(x,y)=x^2e^{-y}+y^2+C

The gradient is continuous for all x,y, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy=f(4,1)-f(1,0)=\frac9e
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3 years ago
. Solve.<br> 2/3 of 3/5 plese help
olasank [31]

Answer:

10/9

Step-by-step explanation:

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2 years ago
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