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3 years ago

Ax+ by = c solve for y

Mathematics

1 answer:

Luden [163]3 years ago

5 0

Answer:

$\boxed{y=\frac{c}{b}-\frac{ax}{b}}$

Step-by-step explanation:

$ax+by=c\\\\ax-ax+by=c-ax\\\\by=c-ax\\\\\frac{by=c-ax}{b}\\\\\boxed{y=\frac{c}{b}-\frac{ax}{b}}$

Hope this helps.

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stepan [7]

Answer:

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3 years ago

What is 14/28 in simplest form?

zhenek [66]

Hi!

The GCM of 14 and 28 is 7. 7 goes into 14 2 times, and goes into 28 4 times. So...

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Which can be simplified further to 1/2

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3 years ago

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the museum wants to display all the art pieces in rows. Each row has the same number of pieces and the same type of pieces. How

Alecsey [184]

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4 years ago

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What is the y-intercept of the function f(x) =-2/9x + 1/3?<br> -2/9<br> -1/3<br> 1/3<br> 2/9

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4 years ago

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A 12 foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the

ira [324]

Using Pythagoras theorem, the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.

Let distance from the wall to the foot of the ladder is 'x' feet and the height of the top of the ladder is 'y' feet.

Pythagoras theorem, $x^{2} + y^{2} = (12)^{2}$ --->(1)

Given, $\frac{dx}{dt}= 2feet/second$ at x=3

Put x=3 in Pythagoras theorem equation (1)

$(3)^{2} + y^{2} = 144$

$y^{2} = 144 - 9$

$y^{2}$ = 135

y = 11.61

Derive equation (1) w.r.t to 't'

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$ ---->(2)

substitute the value of 'x', 'dx/dt' and 'y' in equation (2), we get the fast of the top of the ladder moving down when the foot of the ladder is 3 feet from the wall

$2(3)(2) + 2 (11.61)\frac{dy}{dt} = 0$

12 + 23.22 $\frac{dy}{dt}$ = 0

$\frac{dy}{dt}= \frac{-12}{23.22}$

$\frac{dy}{dt} = -0.518$

Hence, using Pythagoras theorem the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.

Learn more about Pythagoras theorem here

brainly.com/question/21511305

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2 years ago