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AysviL [449]
3 years ago
13

Renna pushed the button for the elevator to go up, but it would not move. The weight limit for the elevator is 450 kilograms, bu

t the current group of passengers weighs a total of 750kilograms. Renna wants to determine how many 70-kilogram passengers need to get off the elevator.
Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0
At least five passengers need to get off
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HELP PLEASE 18 POINTS
Mrrafil [7]

Answer:

75000 centigrams

Step-by-step explanation:

5 0
3 years ago
5k race surveyed runners about their finishing times (f) and the number of previous races they had run (n). The organizers found
vichka [17]
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 
SEE ATTACHED IMAGE, PLEASE.
 
The first thing we must do for this case is to define variables.
 n = number of 5k races covered
 f = end time.
 We have the following equation:
 f = -1.2n + 38.1
 We note that the slope of the line is:
 m = -1.2 minutes per race
 Therefore, the time decreases 1.2 minutes when the number of races increases n.
 Answer:
 
The model predicts that for each additional race to runner has run, the finishing time decreases by about 1.2 minutes

3 0
3 years ago
Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, -3)
madreJ [45]
Paralell is smae slope so it is
2x+3y=c
find c

given
(9,-3)
x=9
y=-3
evaluate to find the constant, c

2(9)+3(-3)=c
18-9=c
9=c

the equation is 2x+3y=9
4 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
Me ayudan xfaaaaaa (':​
IceJOKER [234]

Answer:

2(z + 8) 3 \\

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3 years ago
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