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ikadub [295]
3 years ago
11

Find the sum of 5m + 3n + p, -5p + 3n, and 2n - m

Mathematics
2 answers:
tigry1 [53]3 years ago
7 0
<span>5m + 3n + p -5p + 3n + 2n - m
= 4m + 8n - 4p (combine like terms)

hope it helps</span>
yulyashka [42]3 years ago
4 0
The sum equals 4m+8m-4p
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What is the answer for <br>5 1<br>-= - +d<br>6 3​
givi [52]

Answer:

D=5/2. 5 over 2

Step-by-step explanation:

Cross multiply and solve for D

5 0
3 years ago
Which of the following is an asymptote of y = sec(x)?
babunello [35]
Answer: option d. x = 3π/2

Solution:

function y = sec(x)

1) y = 1 / cos(x)

2) When cos(x) = 0, 1 / cos(x) is not defined

3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...

4) limit of sec(x) = lim of 1 / cos(x).

When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.

So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).

Answer: 3π/2

The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).

8 0
3 years ago
Read 2 more answers
The length if Sally's garden is 4 meters greater than 3 times the width. The perimeter of her garden is 72 meters. Find the dime
ololo11 [35]

Answer: So lets say that the width is w. The length(L) is 4 meters greater than 3 times the width. 3 times the width would be 3w, and then 4 meters greater than that would be 3w+4. You have two widths and two lengths to a rectangle that must add up to equal 72. So 2w + 2L =72. But remember that one L equals 3w+4

2(w) + 2(3w+4) = 72

2w+6w+8=72

8w+8=72

8w=64

w=8

L=3w+4

L=3(8)+4

L=24+4

L=28

So the dimensions are 8 meters by 28 meters

To check 2(8)+2(28)=72

6 0
3 years ago
Thank you for anyone who knows this
katen-ka-za [31]

Answer:  

  • Part (a) Vertex = (-3, -1)
  • Part (b) Vertex = (4, 5)
  • Part (c) function 2; max value = 5

=====================================================

Explanations:

Part (a)

In this case, the vertex is the highest point, so the vertex of function 1 is (-3, -1)

If the parabola was flipped so that it opened upward, instead of downward, then the vertex would be the lowest point.

----------------------------

Part (b)

We could graph this function to see where the highest or lowest point is, but there's another way we could find the vertex using algebra.

The given equation is in the form y = ax^2 + bx + c where in this case

  • a = -2
  • b = 16
  • c = -27

The a and b values are plugged into the formula below to get

h = -b/(2a)

h = -16/(2*(-2))

h = -16/(-4)

h = 4

This is the x coordinate the vertex since the vertex is (h,k)

To find k, we plug that value of h into the original function to find its corresponding y value.

y = -2x^2 + 16x - 27

y = -2(4)^2 + 16(4) - 27

y = -2(16) + 16(4) - 27

y = -32 + 64 - 27

y = 5

We found that h = 4 leads to k = 5. The vertex is (h,k) = (4, 5)

----------------------------

Part (c)

We'll compare the y values of each vertex

  • Function 1 has a vertex of (-3, 1)
  • Function 2 has a vertex of (4, 5)

The vertex with the larger y value is the winner, so that would be function 2. This parabola reaches a higher peak compared to the other curve.

The max value here is y = 5. In other words, it's the maximum output the function can produce.

If you graphed functions 1 and 2 together on the same xy grid (see below), you'll see that the curve for function 2 reaches a higher peak.

7 0
2 years ago
Question 4......................
svp [43]
I would be the last answer because the h of hours would be multiply by 5.
8 0
3 years ago
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