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ikadub [295]
4 years ago
11

Find the sum of 5m + 3n + p, -5p + 3n, and 2n - m

Mathematics
2 answers:
tigry1 [53]4 years ago
7 0
<span>5m + 3n + p -5p + 3n + 2n - m
= 4m + 8n - 4p (combine like terms)

hope it helps</span>
yulyashka [42]4 years ago
4 0
The sum equals 4m+8m-4p
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If the height and base of the parallelogram shown are each increase by oneCM what is the area of the new parallelogram
-Dominant- [34]

Answer:

Let height be h

Base be B

thereforeNew area=(base+1)(hieght+1)

=(b+1)(h+1)

=bh+h+b+1

4 0
3 years ago
Given: -16 = m/5 -18; <br> Prove: m=10
spayn [35]

Answer:

I have proven m is 10. have a good day and give brainliest if possible.

3 0
3 years ago
I need help with question 16.... please help me ????
NeX [460]

Remark

What the question is saying is that you are setting up a proportion. Ordinarily a child would require 125 mg be put into 5 mL of liquid. This child is special and only requires 100 mg. How many mL are needed?

Proportion

125 mg : 5 mL :: 100 mg: x

Solution

125 / 5 = 100 / x               Cross multiply

125x = 500                       Divide by 125

125x/125 = 500/125         Do the division

x = 4

Answer

100 mg would be put in 4 mL of liquid


5 0
4 years ago
Find the answer<br> 29°<br> 36°<br> 49°<br> 61°
Alla [95]
<h3>Answer: Choice A, 29 degrees</h3>

Central angle CBA is a right angle, so it is 90 degrees. This means the arc measure from A to C, following the shortest path on the curve, is 90 degrees. This is minor arc CA. A minor arc is one that is less than 180 degrees in measure.

We want to find the measure of minor arc DE. This is the last piece of the puzzle, so to speak, that forms the entire arc ACD. This arc is 180 degrees because AD is a diameter.

So,

(minor arc DE) + (minor arc EC) + (minor arc CA) = arc ACD

x + 61 + 90 = 180

x + 151 = 180

x + 151 - 151 = 180 - 151 .... subtract 151 from both sides

x = 29

Minor arc DE is 29 degrees.

Check out the attached image below if you're still stuck. Hopefully the image clears any confusion you may have.

5 0
4 years ago
Here are the heights (in inches) of 12 students in a seminar.
Gala2k [10]

Answer: 75%

Step-by-step explanation:

Height given :

69, 62, 73, 67, 63, 65, 73, 71, 70, 66, 59, 75

The total number of height given = 12

The height less than 73 are 69 , 62, 67 ,63 , 65 , 71 , 70 , 66 , 59

The total number of heights less than 73 = 9

Therefore : the percentage of these students who are shorter than 73 inches = total number of students shorter than 73/ total number of height x 100

= 9/12 x 100

= 75%

5 0
3 years ago
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