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scoray [572]
2 years ago
13

Answer the following regarding Momentum Change and Force

Mathematics
1 answer:
trapecia [35]2 years ago
6 0

1. The force necessary to gain a velocity of 60 m/s within 5 mins is 40 N

2. The velocity gained by the object at the end of the second minute is 30 m/s

<h3>1. How to determine the force</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 60 m/s
  • Mass (m) = 200 Kg
  • Time (t) = 5 ms = 5 mins = 5 × 60 = 300 s
  • Force (F) =?

F = m(v –u) / t

F = 200(60 – 0) / 300

F = 40 N

<h3>2. How to determine the velocity </h3>
  • Force (F) = 150 N
  • Mass (m) = 600 Kg
  • Initial velocity (u) = 0 m/s
  • Time (t) = 5 ms = 2 mins = 2 × 60 = 120 s
  • Final velocity (v) = ?

F = m(v –u) / t

Cross multiply

m(v –u) = Ft

Divide both sides by m

v - u = Ft / m

v - 0 = (150 × 120) / 600

v = 30 m/s

Learn more about momentum:

brainly.com/question/250648

#SPJ1

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GREYUIT [131]
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zavuch27 [327]
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3 years ago
MATH HELP???
marin [14]
<h2>Answer:</h2>

The quadratic function are:

 option: A   A)  y(y + 4) - y = 6

 Option: C   C.)  4b(b) = 0

<h2>Step-by-step explanation:</h2>

We know that the general equation of a quadratic equation in terms of a variable x is given by:

   ax^2+bx+c=0

A)

y(y + 4) - y = 6

On simplifying the terms we have:

   y^2+4y-y=6\\\\y^2+3y-6=0

Hence, option: A is correct.

B)

(3x + 2) + (6x - 1) = 0

(3x + 2) + (6x - 1) = 0\\\\i.e.\\\\3x+2+6x-1=0\\\\i.e.\\\\3x+6x+2-1=0\\\\i.e.\\\\9x+1=0

Hence, it is a linear equation.

Hence, option: B is incorrect.

C)

4b(b) = 0

it could also be written as:

4b^2=0

Hence, it is a quadratic equation.

Hence, option: C is correct.

D)

3a - 7 = 2(7a - 3)

3a-7 = 2(7a-3)\\\\i.e.\\\\3a-7=14a-6\\\\\\i.e.\\\\14a-6-3a+7=0\\\\i.e.\\\\14a-3a-6+7=0\\\\i.e.\\\\11a+1=0

which is again a linear equation.

Hence, option: D is incorrect.

6 0
3 years ago
Use zero property to solve the equation.<br> F(x)=3x(x+7)-2(x+7)
oksian1 [2.3K]

Answer:

x = -7 or x = 2/3

Step-by-step explanation:

I'm assuming you meant solve for x when f(x) = 0.

f(x) = 3x(x + 7) - 2(x + 7)

0 = (x + 7)(3x - 2) -- Both terms have a common factor of (x + 7) so we can group them

x + 7 = 0 or 3x - 2 = 0 -- Use ZPP

x = -7 or x = 2/3 -- Solve

7 0
3 years ago
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