
For each subset it can either contain or not contain an element. For each element, there are 2 possibilities. Multiplying these together we get 27 or 128 subsets. For generalisation the total number of subsets of a set containing n elements is 2 to the power n.
Pay attention here because I'm adding an extra letter to our circle to help keep track of the values in our formula. OUTSIDE of the intercepted arc I'm adding the point E. So the major arc is arc BEG and the minor arc is arc BG. The formula then for us is ∠

. We just don't have values for the arcs yet. If the measure of the central angle is 4x+238, then the measure of arcBG is also 4x+238. Around the outside of the circle is 360°. So we will use it in an expression. ArcBEG=360-(4x+238). Fitting that into our formula we have
![2x+146= \frac{1}{2}[(360-4x-238)-(4x+238)]](https://tex.z-dn.net/?f=2x%2B146%3D%20%5Cfrac%7B1%7D%7B2%7D%5B%28360-4x-238%29-%284x%2B238%29%5D%20)
. Doing all the simplifying inside there we have

and

. Multiply both sides by 2 to get rid of the fraction: 4x+292=-8x-116. Combine like terms to get 12x = -408 and divide to solve for x. x = -34. Fourth choice down from the top.
The answer would be 2n^2+3n+ 8n-1
<h2>
Answer:</h2>
The quadratic function are:
option: A A) y(y + 4) - y = 6
Option: C C.) 4b(b) = 0
<h2>
Step-by-step explanation:</h2>
We know that the general equation of a quadratic equation in terms of a variable x is given by:

A)
y(y + 4) - y = 6
On simplifying the terms we have:

Hence, option: A is correct.
B)
(3x + 2) + (6x - 1) = 0

Hence, it is a linear equation.
Hence, option: B is incorrect.
C)
4b(b) = 0
it could also be written as:

Hence, it is a quadratic equation.
Hence, option: C is correct.
D)
3a - 7 = 2(7a - 3)

which is again a linear equation.
Hence, option: D is incorrect.
Answer:
x = -7 or x = 2/3
Step-by-step explanation:
I'm assuming you meant solve for x when f(x) = 0.
f(x) = 3x(x + 7) - 2(x + 7)
0 = (x + 7)(3x - 2) -- Both terms have a common factor of (x + 7) so we can group them
x + 7 = 0 or 3x - 2 = 0 -- Use ZPP
x = -7 or x = 2/3 -- Solve