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Radda [10]
4 years ago
15

Consider points R, S, and T. Which statement is true about the geometric figure that can contain these points? No line can be dr

awn through any pair of the points. One line can be drawn through all three points. One plane can be drawn so it contains all three points. Two planes can be drawn so that each one contains all three points.

Mathematics
2 answers:
Ad libitum [116K]4 years ago
4 0

Answer: The answer is (c) One plane can be drawn so that it contains all three points.


Step-by-step explanation:  We are given three points R, S and T in a coordinate plane. Considering all these three points to be distinct and non-collinear, we can draw the following conclusions.

(i) Since each pairs of points. i.e., (R,S), (S,T) and (T,R) give rise to a straight line when joined, so option (a) is incorrect.

(ii) Through any two given points, we can always draw a line. If we consider a third point and since we are dealing with non-collinear points, so one line cannot be drawn through three points.

(iii)We can always draw a line by joining two points and when we join the two ends of the line to a third point which does not lie on the line, it will give rise to a plane. So, option (c) is correct.

(iv) We cannot draw two different planes through three given points. If we do so, the new plane will coincide with the previous one. This proves that option (d) is not correct.

Please see the attached figure, where P, Q and R are three non-collinear points. They give rise to a plane.

Thus, the correct option is (c).

puteri [66]4 years ago
3 0
Hello,

c- one plane can be drawn so it contains all three points.
(i just took this on a mastery test)
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Answer:

The answer is below

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<u />

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