3 years ago

H(x)=-x^2-4 and I(x)=2x+3 H(I(s))

1 answer:

3 0

Easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
h(I(s))=-(4s^2+12s+9)-4
h(I(s))=-4s^2-12s-9-4
h(I(s))=-4s^2-12s-13

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And replacing we got:

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Step-by-step explanation:

Let X the random variable of interest "number of craked eggs", on this case we now that:

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And we can find the probability:

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And replacing we got:

$P(X \geq 1) = 1-0.9801 = 0.0199$

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Read 2 more answers