All categories

3 years ago

39 times 49 times 81

Mathematics

2 answers:

Sav [38]3 years ago

8 0

Answer:

39 times 49 times 81 = 154791

d1i1m1o1n [39]3 years ago

7 0

Answer:

154,791

Step-by-step explanation:

You might be interested in

Which rational number is one tick mark to the left of -3/4

Zolol [24]

I'm assuming each tickmark is 1/4 = 0.25

If that assumption is correct, then going one tickmark to the left of -3/4 lands you on -4/4 which simplifies to -1.

So -1 is one tickmark to the left of -3/4

Again, this all hinges on the assumption that each tickmark is 1/4 a unit away from its neighbor.

5 0

3 years ago

Which of the following could be a function with zeros of —3 and 2? А f(x) = (x - 3)(x + 2) B f(x) = (x = 3)(x - 2) © f(x) = (x+3

Zinaida [17]

Answer:

Step-by-step explanation:

to find the zeros you look at what value you would fill in for x to make zero, so (x+3) would have a zero of -3 and (x-2) would have a zero of 2

6 0

3 years ago

The graph of the function f(x) = (x +2)(x + 6) is shown below. What is true about the domain and range of the function? The doma

Vinil7 [7]

the answer is The domain is all real numbers, and the range is all real numbers greater than or equal to –4.

10 0

3 years ago

Read 2 more answers

How many significant figures are there In the number 10.76

VikaD [51]

Answer:

Number of Significant Figures: 4

The Significant Figures are 1 0 7 6

3 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago