Answer:
C
Step-by-step explanation:
Answer:
Step-by-step explanation:
Count pairs (a, b) whose sum of squares is N (a^2 + b^2 = N)
Given a number N, the task is to count all ‘a’ and ‘b’ that satisfy the condition a^2 + b^2 = N.
Note:- (a, b) and (b, a) are to be considered as two different pairs and (a, a) is also valid and to be considered only one time.
Examples:
Input: N = 10
Output: 2
1^2 + 3^2 = 9
3^2 + 1^2 = 9
Input: N = 8
Output: 1
2^2 + 2^2 = 8
Y = 8x - 2
y = 9x - 7
8x - 2 = 9x - 7
- 8x - 8x
-2 = x - 7
+ 7 + 7
5 = x
y = 8x -2
y = 8(5) - 2
y = 40 - 2
y = 38
(x, y) = (5, 38)
The answer is C.
<span>interest = $580 x 0.065 = $37.70
answer
interest for the year is </span>$37.70
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
