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2 years ago

Solve -2x ≤ -4. Graph the solution

Mathematics

1 answer:

horsena [70]2 years ago

3 0

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Solve for x. x÷(-2)=1.4

nignag [31]

Answer:

x=-2.8

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Using the figure below, find the lengyh of x.

katrin [286]

Answer:

what i don't understand why you are not answer that question

5 0

3 years ago

Two points A and B on a plan represent two localities 12 m apart. Given that the segment AB is 6cn long, find the scale used to

natka813 [3]

Answer:

The scale is 1:200

Step-by-step explanation:

On the plan we have the drawing as 6 cm

In real representation, we have the distance as 12 m

Firstly we have to convert to same unit

In this case, we use the cm for convenience

Mathematically, 100 cm is 1 m

Thus, 12 m

will be 12 * 100 = 1,200 cm

So, we have the ratio as;

6 cm : 1,200 cm

and that is 1:200 (since 6/1200 = 1/200 and in ratio form, we have that as 1:200)

7 0

2 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

2 years ago

A drawing of a rectangular garden is 5 inches and a width of 3.5 inches. The scale is 1 in: 3 ft. What is the length and width o

horrorfan [7]

5•3=15, 3.5•3=10.5....... the regular length of the length and width is :::::: LENGTH= 10.5 feet..... HEIGTH=15 feet

4 0

2 years ago