How many students would there be? did not see that information if that is the question but if not I say go with the bus that has more seats yes it is more expensive but more space is better!
32 because 4x8=32. if u need anything else please post it here
Machine J's equation would be 30x=y. To find out how many more candies Machine J packets, You would plug in 11 as x and you would get 330.
For Machine K, you would just plug in 11 as x. Your answer is 286.
Now you would subtract. 330-286=44.
Answer:
-$13.5
Step-by-step explanation:
Let x be a random variable of a count of player gain.
- We are told that if the die shows 3, the player wins $45.
- there is a charge of $9 to play the game
If he wins, he gains; 45 - 9 = $36
If he looses, he has a net gain which is a loss = -$9
Thus, the x-values are; (36, -9)
Probability of getting a 3 which is a win is P(X) = 1/6 since there are 6 numbers on the dice and probability of getting any other number is P(X) = 5/6
Thus;
E(X) = Σ(x•P(X)) = (1/6)(36) + (5/6)(-9)
E(X) = (1/6)(36 - (5 × 9))
E(X) = (1/6)(36 - 45)
E(X) = -9/6 = -3/2
E(X) = -3/2
This represents -3/2 of $9 = -(3/2) × 9 = - 27/2 = -$13.5
Answer:
x < -16, none of the solution sets are correct for the given equation.
Step-by-step explanation:
-1/4x > 4, multiply both sides by -4, don't forget when you multiply or divide by a negative you have to flip the sign.
x < -16
none of the solution sets are correct for the given equation.
