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4 years ago

Decrease seventy two hundredths by two tenths

1 answer:

5 0

seventy two hundredths = 0.72.

Decrease = Subtraction.

Two Tenths = 0.2

So:

0.72 - 0.2

0.72 - 0.2 = 0.52

So, This Expression Is Equal To 0.52

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At the first meeting of the Tennis Club, the 7 members decided to have a tournament in which every player will play a match agai

mariarad [96]

Answer:

21 matches

Step-by-step explanation:

This is a combination problem where we have to select two member out of 7 members

So we want calculation of 7C2

7C2 = 7!/[(2!)(7-2)!]

(7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]

(7*6)/2 ~ Note everything that easily cancels here!

42/2

21 matches

5 0

3 years ago

Irrational number between 2 and 3

ziro4ka [17]

Answer:

2.084...

Step-by-step explanation:

Just write an non repeating string of any numbers that you think of but not in a pattern which will lie between decimal value of your 2 numbers

6 0

3 years ago

The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological testdeveloped to measure the degree of Mexican/S

maria [59]

Answer:

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

(2.13264 , 2.58736)

Step-by-step explanation:

Step(i):-

Mean of the Population = 3.0

Standard deviation of the Population = 0.8

Given Mean of the sample(x⁻ ) = 2.36

Standard deviation of the sample (S) = 0.8

size of the sample = 50

Level of significance =0.05

Degrees of freedom = n-1 = 50-1 = 49

$t_{\frac{0.05}{2} , 49} = 2.0096$

Step(ii):-

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

$(x^{-} - t_{(\frac{\alpha }{2},df )} \frac{S}{\sqrt{n} } , (x^{-} +t_{(\frac{\alpha }{2},df )} \frac{S}{\sqrt{n} })$

$(2.36 - 2.0096 \frac{0.8}{\sqrt{50} } , 2.36 +2.0096\frac{0.8}{\sqrt{50} })$

( 2.36 - 0.22736 , 2.36 + 0.22736)

(2.13264 , 2.58736)

Final answer:-

95% confidence interval for the mean ARSMA score for first-generation Mexican Americans

(2.13264 , 2.58736)

7 0

3 years ago

Leanne runs a lap in 12 minutes. Kory runs a lap in 9 minutes. If they

klemol [59]

Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .

Step-by-step explanation:

Here we have , Leanne runs a lap in 12 minutes. Kory runs a lap in 9 minutes. We need to find out that If they both start running at 10 am, at what time will they both cross the start together again . Let's find out:

Kory runs a lap in 9 minutes and , Leanne in 12 minutes , in order to find at what time will they both cross the start together again we will find LCM of 9 & 12 :

⇒ $\frac{9(4)}{12(4)}$

⇒ $\frac{36}{36}$

So ,LCM of 9 & 12 is 36 .That means Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .

In clear way , Kory will run race as :

1st lap = 9 minutes

2nd lap = 18 minutes

3rd lap = 27 minutes

4th lap = 36 minutes , i.e. at 10:36 am he'll complete his 4th lap

For , Leanne

1st lap = 12 minutes

2nd lap = 24 minutes

3rd lap = 36 minutes i.e. at 10:36 am he'll complete his 3rd lap .

This means Kory & Leanne will meet at 10:36 am completing there 4th and 3rd lap respectively .

6 0

4 years ago

An electric company has to track on-time payments and late payments for each customer monthly. It is impossible for a customer t

OLga [1]

Answer:

The probability that a customer pays late each month is P(B) = 0.27

Step-by-step explanation:

Let P( A ) be the probability that the customer pays on time and the value is 0.55

Let P( B ) be the probability that a customer pays late each month

The probability that a customer pays late or on-time each month is P(A u B) and the value is 0.82

The probability that a customer pays on-time and late each month is P(A n B) and the value is zero ( 0 ) given that it is impossible

Now The probability that a customer pays late or on-time each month is mathematically represented as

P(A u B) = P(A) + P(B) - P(A n B)

=> 0.82 = 0.55 + P( B ) - 0

=> P(B) = 0.27

8 0

3 years ago