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Bingel [31]
3 years ago
8

What is the length of segment GH?

Mathematics
2 answers:
MissTica3 years ago
7 0

Answer:

\sqrt{80} units

Step-by-step explanation:

We have to find the length of segment GH.

Since coordinates of G and H are G(0, 3) and H(8, 1)

Now we know if coordinates of the end points of a line segment have been given then length of the segment will be

\sqrt{(x-x')^{2}+(y-y')^{2}}

\sqrt{(8-0)^{2}+(1+3)^{2}}

\sqrt{64+16}

\sqrt{80} units

Option c \sqrt{80} units is the answer.

mr Goodwill [35]3 years ago
6 0

Answer:

\sqrt{80}

Step-by-step explanation:

To calculate the distance GH use the distance formula

GH = √ ( x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = G(0, - 3) and (x₂, y₂ ) = H(8, 1)

GH = \sqrt{(8-0)^2+(1+3)^2}

     = \sqrt{64+16} = \sqrt{80}

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Answer:

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Step-by-step explanation:

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Where the point of the line are: (x₁;y₁) and (x₂;y₂).

In the problem, x₁ = 2.6, y₁ = 5.1 and x₂ = 3 and y₂ = 4.7. Replacing in the equation:

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Q13. y = sin(2x – π/2); y = - 2cos2x  

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Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

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B. Cosine function

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Question 14

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Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

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