Harold paid $ 16,632 and $ 38,808 for each of the boats.
Since Harold, a marina manager, purchased two boats, and he then sold the boats, the first at a profit of 40% and the second at a profit of 60%, and the total profit on the sale of the two boats was 54 % and $ 88 704 was the total selling price of the two boat, to determine what did Harold originally pay for each of the two boats the following calculation must be performed:
- 55 x 0.6 + 45 x 0.4 = 51
- 65 x 0.6 + 35 x 0.4 = 53
- 70 x 0.6 + 35 x 0.4 = 54
- 88,704 x 0.7 = 62,092.80
- 160 = 62,092.80
- 100 = X
- 100 x 62,092.80 / 160 = X
- 38.808 = X
- 88,704 x 0.3 = 26,611.20
- 140 = 26,611.20
- 100 = X
- 100 x 26,611.20 / 160 = X
- 16,632 = X
Therefore, Harold paid $ 16,632 and $ 38,808 for each of the boats.
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4 load= 666. never ending 6
4/4 load= 666. never ending 6 / 4
1 load= 166. never ending 6
1 load = 167kg rounded
To find the ratio, you Will need to find the ratio of the patio, and the ratio of the scale version of the patio.
16 feet x 20 feet = 320 ft.²
(16/4 = 4 in)/(20/4= 5 in)
4 inches x 5 inches = 20 in.²
320 ft.² / 20 in.² = 16 ft.² / 1 square inch
X= 75/2
Y=0
That is the answer to your question I used Photomath to help me
