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4 years ago

- 6x+4=-2 algebra question

1 answer:

7 0

You need to get x= something.

To do this, you -4 on both sides to leave you with just an x value on the left. This gives -6x=-6

Then you need x on its own, so you divide both sides by -6.

-6/-6= 1, so x=1

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Sophie [7]

since the equation is c=9.5t, Sanjay paid c=9.5 x 14 shirts he bought. which =$133

6 0

3 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

3 years ago

Jim owns an ice-cream store. Use the clues to find out how many ice-cream cones he sold last week. • He sold more than 300 but f

allsm [11]

Answer:

Step-by-step explanation:

Remark

The last digit is 1 3 5 7 9 because the last digit is odd.

The first digit must be a 3 because the number is between 300 and 350

Let the first digit = x

Let the second digit = y

Let the third digit = z

x + y = z

x + y + z = 14 Substitute z for x + y

z + z = 14 Combine

2z = 14 Divide by 2

2z/2 = 14/2

z = 7

The first digit is 3 and the third digit = 7

The middle digit is 3 less than the last digit.

y = 7 - 3 = 4

Answer

347

4 0

2 years ago

A bag contains green marbles and blue marbles, 18 in total. The number of green

Katena32 [7]

Answer:

Step-by-step explanation:

Let the number of blue marbles be x

The number of green marbles = 3x - 2

Total marbles= 18

x + 3x -2 = 18

4x - 2 = 18

4x = 18+2

4x = 20

x =20/4

x =5

The number of blue marbles = 5

The number of green marbles = 3*5 - 2 = 15 -2 = 13

5 0

3 years ago

How many pairs of number equal the sum of 12

aleksley [76]

Total numbers of whole number that has a sum of 12.
1. 11 + 1 = 12
2. 10 + 2 = 12
3. 9 + 3 = 12
4. 8 + 4 = 12
5. 7 + 5 = 12
6. 6 + 6 = 12
7. 12 + 0= 12

so there are 7 pairs of whole numbers being added that have a sum of 12

7 0

3 years ago

- 6x+4=-2 algebra question​

- 6x+4=-2 algebra question