Question

Sodium hydroxide (NaOH) and hydrochloric acid (HCl) react to form sodium chloride (NaCl) and water according to the equation:

Answer 1

Answer:

0.00496

Step-by-step explanation:

e2020

Answer 2

Answer: The mass of $H_2O$ formed will be $4.95\times 10^{-3}$ grams

Explanation:

For the given reaction:

$NaOH+HCl\rightarrow NaCl+H_2O$

By Stoichiometry of the reaction:

1 mole of NaCl produces 1 mole of water molecule.

So, $2.75\times 10^{-4}mol$ of NaCl will produce $2.75\times 10^{-4}mol$ of $H_2O$

To calculate the mass of water, we will use the equation used to calculate number of moles, which is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Number of moles of $H_2O=2.75\times 10^{-4}$ moles

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

$2.75\times 10^{-4}mol=\frac{\text{Given mass}}{18g/mol}\\\\\text{Given mass of water}=4.95\times 10^{-3}g$

Hence, the mass of $H_2O$ formed will be $4.95\times 10^{-3}$ grams