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Evgen [1.6K]
3 years ago
15

Tyna simplified the expression 3x^3/12x^-2 to x/4. What was Tyna’s mistake?

Mathematics
2 answers:
Levart [38]3 years ago
6 0
B) She added the exponents instead of subtracting them.
Ksenya-84 [330]3 years ago
4 0

We are given expression: \frac{3x^3}{12x^{-2}}.

Tyna simplified the given expression to \frac{x}{4}.

Explanation: In order to simplify \frac{3x^3}{12x^{-2}}, Tyna need to simplify rational expression \frac{3}{12}.

On dividing top and bottom by 3, we get \frac{1}{4}.

Which Tyna got correct.

Now she need to simplify \frac{x^3}{x^{-2}}.

<em>On applying quotient rule of exponents, we need to subtract the exponents of x's.</em>

So, it would be \frac{x^3}{y^-{2}} = x^3-{-2} = x^{3+2} = x^5.

<h3>So, the final answer should be \frac{x^5}{4}.</h3><h3>Therefore, Tyan forgot to add exponent to x.</h3><h3>The exponent of x should be 5.</h3>
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A number is divided by 3. Then 14 is added to the quotient. The result is 33. What is the orginal number?
seropon [69]

let "a number" = x

a number is divided by 3 => x/3

14 is added to the quotient => (x/3) + 14

The result is 33 => " = 33"

Solve for x

(x/3) + 14 = 33

Isolate the x. Note the equal sign. What you do to one side you do the other.

Subtract 14 from both sides

(x/3) + 14 (-14) = 33 (-14)

x/3 = 19

Isolate the x. Multiply 3 to both sides

x/3(3) = 19(3)

x = 19(3)

x = 57

57 is your original number

hope this helps

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2 years ago
Please explain how to do it because im very confused please and thank you!!!!!!!
mezya [45]

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Step-by-step explanation:

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Solving :

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4 0
1 year ago
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2 years ago
If log 5 = p and log 2=q then log 200 can be written in terms of p and q as?
Andrei [34K]
<h3>Answer:  2p + 3q</h3>

Work Shown:

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