Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z = ~ N(0,1)
where, = population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P( < ) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
Answer:
x = 18
Step-by-step explanation:
Given:
Finding x for which 3b = 5a:
- 3(4x - 7) = 5(2x + 3)
- 12x - 21 = 10x + 15
- 12x - 10x = 15 + 21
- 2x = 36
- x = 36/2
- x = 18
-8x - 60 = -164
Add 60 to both sides, because whatever you do on one side, you have to do it to the other side
-8x = -104
Divide -8 to both sides
x = 13
Answer:
Huh?? I have no idea what you said.
Step-by-step explanation: