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g100num [7]
3 years ago
14

Y = –3x2 – 12 Axis of symmetry:

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
<h3>Answer:   x = 0</h3>

Work Shown:

y = -3x^2 - 12 is the same as y = -3x^2 + 0x + (-12)

Compare this to y = ax^2 + bx + c, and we'll find that

a = -3

b = 0

c = -12

Plug the 'a' and 'b' values into the formula below and simplify

h = -b/(2a)

h = -0/(2*(-3))

h = 0

The x coordinate of the vertex is x = 0, so the axis of symmetry is also x = 0.

The axis of symmetry lays perfectly on top of the y axis.

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Solve the equation y = 200 - 5(x + 37) for x if y = 360.
julsineya [31]

Answer:

x= -35.153846

Step-by-step explanation:

360=200-5(x+37)

360=195(x+37)

360=195x+7215

360-7215=195x+7215-7215

-6855=195x

-6855/195=195x/195

-35.1538461538=x

-35.153846=x

I THINK ;]

7 0
3 years ago
the ratio of the temperature of room S to the temperature of room T is 2:3 and the ratio of the temperature of room T to the tem
zalisa [80]

Step-by-step explanation:

s:t=2:3

t:u=2:3

s:u=?

s/u=2/3

5 0
2 years ago
How to solve this? Please explain your answer! Thanks!
Murrr4er [49]

Answer:

The mean.

Step-by-step explanation:

I would use the mean as the measure of central tendency.

It is the best representation of the data as the variability isn't high; I'd only use the median if outliers are present because outliers don't affect it.

Because there are no outliers here, the mean is better.

Hopefully I helped :)

4 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
maxonik [38]

Answer:

Assume that Sk is valid for n=k and prove that Sn is valid for n= k+ 1

Step-by-step explanation:

This is Principle of Mathematical Induction ---PMI

Step 1: Verify that Sn is valid for n =1

Step 2:Assume that Sk is valid for n=k and prove that Sn is valid for n= k+ 1

6 0
3 years ago
Write an unit rate for this situation.<br> traveling 426 miles in 7 hours.
balu736 [363]

Answer:

60.857 miles /hour

Step-by-step explanation:

the unit rate is miles per hour

426 miles / 7 hours

60.857 miles /hour


6 0
3 years ago
Read 2 more answers
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