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3 years ago

A rectangle has a length of 2x 5 units and a width of , 3 units. What is the area, in square

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Answer:

$2 {x}^{2} - 11x + 15$

Step-by-step explanation:

We we're given the length of the rectangle as

$l = 2 {x} - 5$

and the width of the rectangle as :

$w = x - 3$

Recall that, the area of a rectangle is

Area=l×w

We substitute the given dimensions of the rectangle into the formula to get:

$area =( 2 {x} - {5} ) \times(x - 3)$

We expand

$2 {x}^{2} - 6x - 5x + 15$

This simplifies to:

$2 {x}^{2} - 11x + 15$

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3 years ago

What solution is correct for 4 x + 5 = 9 + 4 x

Bess [88]

Answer:

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Add you like terms. 4x plus 4x equals 8x. Then 5 plus 9 equals 14 so then you have 8x= 14 divide by eight on both sides and there you go.

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3 years ago

In a survey of 155155 senior executives, 48.448.4% said that the most common job interview mistake is to have little or no kno

victus00 [196]

Answer:

We conclude that in the population of all senior executives, different from 40% say that the most common job interview mistake is to have little or no knowledge of the company.

Step-by-step explanation:

We are given that in a survey of 155 senior executives, 48.4% said that the most common job interview mistake is to have little or no knowledge of the company.

We have to use a 0.05 significance level to test the claim that in the population of all senior executives, 40% say that the most common job interview mistake is to have little or no knowledge of the company.

Let p = population proportion of senior executives who said that the most common job interview mistake is to have little or no knowledge of the company

So, Null Hypothesis, $H_0$ : p = 40% {means that in the population of all senior executives, 40% say that the most common job interview mistake is to have little or no knowledge of the company}

Alternate Hypothesis, $H_A$ : p $\neq$ 40% {means that in the population of all senior executives, different from 40% say that the most common job interview mistake is to have little or no knowledge of the company}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of senior executives who said that the most common job interview mistake is to have little or no knowledge of the company = 48.4%

n = sample of senior executives = 155

So, the test statistics = $\frac{0.484-0.40}{\sqrt{\frac{0.484(1-0.484)}{155} } }$

= 2.09

The value of z test statistics is 2.09.

Also, P-value of the test statistics is given by;

P-value = P(Z > 2.09) = 1 - P(Z $\leq$ 2.09)

= 1 - 0.9817 = 0.0183

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that in the population of all senior executives, different from 40% say that the most common job interview mistake is to have little or no knowledge of the company.

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4 years ago

Solve the equation. -8/5b = 5 b=

neonofarm [45]

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