Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
Step-by-step explanation:
Since the line segment is only being translated and reflected it would still maintain its length. This is pretty much the only characteristic that would remain the same as te original line segment. It would not maintain the same x-axis positions for both endpoints of the line segment. This is because when it is translated 2 units up it is only moving on the y-axis and not the x-axis. But when it is reflected over the y-axis the endpoints flip and become the opposite values.
Answer:
<h2>
RS = 47</h2>
Step-by-step explanation:
RV=VU and SW=WT ⇒ 
Therefore:

3x + 5 = 4x - 11 {subtract 5 from both sides)
3x = 4x - 16 {subtract 4x from both sides)
-x = -16 {divide both sides by (-1)}
x=16
So:
RS = 2x + 15 = 2×16 + 15 = 32 + 15 = 47
B is the best strategy. (You mentioned an option D, but it's not shown in your question!!)