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The slope of the line that contains the point (13,-2) and (3,-2) is 0
<em><u>Solution:</u></em>
Given that we have to find the slope of the line
The line contains the point (13,-2) and (3,-2)
<em><u>The slope of line is given as:</u></em>

Where, "m" is the slope of line
Here given points are (13,-2) and (3,-2)

<em><u>Substituting the values in formula, we get,</u></em>

Thus the slope of line is 0
Answer:
Step-by-step explanation:

Answer:
The E. Coli will grow at a rate of approximately 800% an hour.