The complete question is <span>Four golf balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylinder. The diameter of each ball is 4cm. 1) </span><span>What is the volume of the cylinder rounded to the nearest cubic centimeter? </span>2) <span>What is the total volume of the four balls rounded to the nearest cubic centimeter? </span>3) <span>What percent of the volume of the container is occupied by the four balls? </span><span> Part 1) volume of the cylinder=pi*r</span>²*h <span>r=4/2----> 2 cm h=4*4----> 16 cm </span>volume of the cylinder=pi*2²*16----> 200.96 cm³----> 201 cm³
the answer Part 1) is 201 cm³
Part 2) volume of a sphere=(4/3)*pi*r³ ( is equal to volume of one <span>golf ball) </span>r=2 cm volume of a sphere=(4/3)*pi*2³ ----> 33.49 cm³ so volume of four golf ball-----> 4*33.49----> 133.97 cm³----> 134 cm³
the answer part 2) is 134 cm³
part 3) volume of cylinder=201 cm³ volume of the four golf ball=134 cm³ so if 201 cm³-----------> 100% 134 cm³--------> x x=134*100/201----> x=66.67%
As ◇H is less than 0 and T◇S is greater than 0 so if we put it in the equation we would get the negative maximum result. And when the energies are with negative sign they are said to be spontaneous.
