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docker41 [41]
3 years ago
6

What is the domain and range for the following function and it’s inverse ? Help needed !!!

Mathematics
1 answer:
Pie3 years ago
5 0

ANSWER

f(x)

Domain:(-∞,∞)

Range:(-∞,∞)

{f}^{ - 1} (x)

Domain:(-∞,∞)

Range:(-∞,∞)

The given function is

f(x) =  \frac{3x - 1}{2}

This is a polynomial function.

All polynomial functions are defined everywhere.

The domain is all real numbers.

Or

(-∞,∞).

The range is also all real numbers.

(-∞,∞).

The domain of the inverse function equals the range of the function.

(-∞,∞).

The range of the inverse function equals the domain of the function.

(-∞,∞).

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Supose that the half-life of a cesium is 30 years. If there were initially 1000g of the substance,
AveGali [126]

After 200 years, 9.84 grams of Cesium would remain.

Let N represent the amount of substance after t years

The half-life of a cesium is 30 years., hence, this can be represented by exponential function:

N(t)=ab^t

where a is the initial value and b is the multiplier.

There were initially 1000g of the substance

a) The exponential model for this situation is:

N(t) =1000(\frac{1}{2} )^{\frac{1}{30} t}\\\\N(t) =1000(\frac{1}{2} )^{\frac{t}{30}

b) After 200 years (t = 200), the amount of Cesium remaining is:

N(200)=1000(\frac{1}{2} )^\frac{200}{30} \\\\N(200) = 9.84g

Hence after 200 years, 9.84 grams of Cesium would remain

Find out more at: brainly.com/question/24710827

8 0
3 years ago
Which expression is equivalent 8(2s + 6)
zvonat [6]

Answer:

16s + 48

Step-by-step explanation:

8(2s + 6) ← multiply each term in the parenthesis by 8

= 16s + 48

5 0
3 years ago
Read 2 more answers
What is the sum of ​​​​​​12,837.45 and 15,910.65? Enter your answer in the box below.
Minchanka [31]

Answer: 28748.1

Step-by-step explanation:

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bcos%2030%7D%7B1%2Bsin30%7D%3Dtg30" id="TexFormula1" title="\frac{cos 30}{1+sin30}=tg
Kay [80]

\cos 30=\frac{\sqrt{3}}{2}

\sin 30 = \frac{1}{2}

\tan 30=\frac{1}{\sqrt{3}}

Now we insert that into the equation:

\dfrac{\frac{\sqrt{3}}{2}}{1+\frac{1}{2}} = \frac{1}{\sqrt{3}}

\dfrac{\frac{\sqrt{3}}{2}}{\frac{3}{2}} = \frac{1}{\sqrt{3}}

\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}

\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}\\

\frac{\sqrt{3}}{3} = \frac{\sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}\\

\frac{\sqrt{3}}{3} = \frac{\sqrt{3}}{3}

6 0
4 years ago
One a piece of paper graph y=–3x–2.Then determine which answer matches the graph you Drew.
alina1380 [7]
For this case we have the following equation:
 y = -3x-2
 The slope of the line is:
 m = -2
 The cut point with the x axis is:
 (-2/3, 0)
 The cut point with the y axis is:
 (0, -2)
 Answer
 
See attached image.

8 0
3 years ago
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