Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30
substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w
substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w
substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15
insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16
B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2
Answer:
4/8 and then 1/2so 1/2 is the final answer
Answer:
y = 2/3x - 13
Step-by-step explanation:
We have a slope of 2/3 and a point (9, -7)
The point slope form of a line is
y-y1 = m(x-x1)
y--7 = 2/3 (x-9)
Distribute
y+7 = 2/3x - 6
Subtract 7 from each side
y+7-7 = 2/3x -6-7
y = 2/3x - 13
This is in slope intercept form.
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The answer is 1 19/25
Hope this helps!
