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3 years ago

The us is 3.794 million square miles approximately 650000 square miles are work production what percent is?

1 answer:

3 0

The total land available in the US = 3.794 million square miles which is 3,794,000 square miles
The land used for food production is 650, 000 square miles

To find the percentage used in food production, we divide the land used in food production by the total land and multiply the quotient by 100.
Percent for food =
(650, 000/3, 794, 000) * 100

Percentages land used for food
= 17.13%

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A movie theater sends out a coupon for 75% off the price of a ticket. Write an equation for the situation, where y is the pric

Fed [463]

Answer:

x divided by 75% = y

Step-by-step explanation:

3 0

3 years ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.

Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Step-by-step explanation:

GIven that:

$f(x) = 5e^{-x^2} cos (4x)$

The Maclaurin series of cos x can be expressed as :

$\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+... \ \ \ (1)}$

$\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0} \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!} -\dfrac{x^6}{3!}+... \ \ \ (2)}$

From equation(1), substituting x with (4x), Then:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}$

The first three terms of cos (4x) is:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}$

$\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}$

$\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}$

Multiplying equation (2) with (3); we have :

$\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Finally , multiplying 5 with $\mathtt{ e^{-x^2} cos (4x) }$ ; we have:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

7 0

4 years ago

Can someone help me plz

Alexxx [7]

Answer:

8 -4 -7 1

Step-by-step explanation:

bc it you put them the same way you can tell witch one is bigger

8 0

4 years ago

Read 2 more answers

JulijaS [17]

Answer:

B. 1 + ln 2 - ln x

General Formulas and Concepts:

Algebra II

Natural logarithms ln and Euler's number e
Logarithmic Property [Multiplying]: $\displaystyle log(ab) = log(a) + log(b)$
Logarithmic Property [Dividing]: $\displaystyle log(\frac{a}{b}) = log(a) - log(b)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle ln(\frac{2e}{x})$

Step 2: Simplify

Expand [Logarithmic Property - Dividing]: $\displaystyle ln(\frac{2e}{x}) = ln(2e) - ln(x)$
Expand [Logarithmic Property - Multiplying]: $\displaystyle ln(\frac{2e}{x}) = ln(2) + ln(e) - ln(x)$
Simplify: $\displaystyle ln(\frac{2e}{x}) = ln(2) + 1 - ln(x)$
Rewrite: $\displaystyle ln(\frac{2e}{x}) = 1 + ln(2) - ln(x)$

4 0

3 years ago

The sea turtle dove down in the ocean 12 meters. Later the sea turtle was chasing his dinner of fish and dove 7 more meters.

Zigmanuir [339]

If you are trying to find how deep the turtle is now, the answer would be 19 meters. 12 + 7 = 19.

Hope this helps. Have a nice day.

3 0

3 years ago