The equation of the line in slope-intercept form is y = (1/2)x + 3 and the slope is 1/2.
<h3>What is a straight line?</h3>
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
![\rm m =\dfrac{y_2-y_1}{x_2-x_1}\\](https://tex.z-dn.net/?f=%5Crm%20m%20%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%5C%5C)
As we can see in the graph the line goes from (-6, 0) and (0, 3)
Finding the slope:
![\rm m =\dfrac{3-0}{0-(-6)}\\](https://tex.z-dn.net/?f=%5Crm%20m%20%3D%5Cdfrac%7B3-0%7D%7B0-%28-6%29%7D%5C%5C)
m = 3/6 = 1/2
y = mx + c
y = (1/2)x + c
c is the y-intercept
c = 3
The equation:
y = (1/2)x + 3
Thus, the equation of the line in slope-intercept form is y = (1/2)x + 3 and the slope is 1/2.
Learn more about the straight line here:
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75% of 12 can be represented with the equation 75/100=x/12
Then to solve
75(12)= 100x
900 = 100x
9=x
So the distance from the school to the park is 9 miles.
Answer:
Width=6.5 cm
Length=12 cm
Step-by-step explanation:
Step 1: Express the lengths and widths
Width=w
Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1
Step 2: Solve for the length and width
A=L×W
where;
A=area of the photograph
L=length of the photograph
W=width of the photograph
In our case;
A=91 cm²
L=2 w-1
W=w
91=(2 w-1)w
2 w²-w=91
2 w²-w-91=0, is a quadratic equation
solve for w
w={-1±√(-1²-4×2×-91)}/(2×2)
w=(-1±27)/4
w=(27-1)/4=6.5, or (-1-27)/4=-8
Take w=6.5 cm
L=(2×6.5)-1=13-1=12 cm
Width=6.5 cm
Length=12 cm
Answer:
The answer to your question is x = 64; y = 20
Step-by-step explanation:
Angles 2x + 2 and 130° are vertical angles so they measure the same.
2x + 2 = 130
- Solve for x
2x = 130 - 2
2x = 128
x = 128/2
x = 64
Angles 3y - 10 and 50° are vertical angles, so they measure the same.
3y - 10 = 50
3y = 50 + 10
3y = 60
y = 60/3
y = 20