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bezimeni [28]
4 years ago
14

What is an equation of the line that passes through the points (4, -4) and (-4,-4)?

Mathematics
1 answer:
aalyn [17]4 years ago
4 0

Answer:

y=-4

Step-by-step explanation:

i think its right

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A resturant sells 10 tacos for 8.49,or 6 of the same kind of taco for 5.40.Which is a better deal
Aliun [14]

Answer:

10 tacos for 8.49 because 6 tacos for 5.40 it's almost a dollar for each.And the deal 10 tacos for 8.49 you pay more but it's better it's not a dollar for each it's like 84 cents for each

3 0
3 years ago
Tan θ sin θ + sin θ = 0 . Solve the given equation.
VashaNatasha [74]
Here's a PDF file with the solution... Powered by Wolfram Mathematica
Download pdf
4 0
3 years ago
The perimeter of a rectangle is 60 m and its length is twice its width. find the length of the rectangle
GREYUIT [131]
Length = 2W

P= 2L + 2W
60 = 2(2W) + 2W
60= 4W +2W
60 = 6W
60/6W = 6W/6W
w = 10
Length = 2(10)
Length = 20

P= 2L + 2W
60= 2(20) + 2(10)
60= 40 +20
60 = 60
4 0
3 years ago
Which one goes first a negative or a positive
Zielflug [23.3K]

no number can have a positive and a negative at the same time. a negative number has a negative sign and a positive number has a plus sign.

6 0
4 years ago
Can someone solve this?
ladessa [460]
  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|

For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

6 0
3 years ago
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