Answer:
<em>The expression that represents her gross pay each day will be:
dollars.</em>
Step-by-step explanation:
Suppose, Harriet's gross pay each day 
So, her total gross pay for 7 work days 
Given that, her gross pay at the end of 7 work days is
dollars.
So, the equation will be.......

Thus, the expression that represents her gross pay each day will be:
dollars.
I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

Answer:
3
Step-by-step explanation:
15 men would be left
5 women would be left
12a)
5x + 45 + 3x - 25 = 180
8x + 20 = 180
8x = 160
x = 20
12b)
2x - 5 = 2(20) - 5 = 40 - 5 = 35
3x - 25 = 3(20) - 25 = 60 - 25 = 35
y = 180 - (35+35)
y = 180 - 70
y = 110