Answer:
purple
Step-by-step explanation:

Suppose we choose a path along the

-axis, so that

:

On the other hand, let's consider an arbitrary line through the origin,

:

The value of the limit then depends on

, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
The probability that “a child ticket is bought for a play” and “the play is performed in the afternoon" is 36/363.
<h3>What is the probability?</h3>
Probability is the likelihood that a stated event would occur. The probability that the event would happen lies between 0 and 1.
The probability that “a child ticket is bought for a play” and “the play is performed in the afternoon" = 36 / total number of tickets bought
36 / (36 + 12 + 127 + 188) = 36 / 363
To learn more about probability, please check: brainly.com/question/13234031
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Answer:
22?
Step-by-step explanation:
Just take 40 and subtract the 7 to get 33 and then 2 to get 31 and 9 to get 22.
3y+7=31
3y=24 (we subtracted 7 from both sides)
24 divided by 3 is 8
Y=8