For the given function, the domain is D : { x ≥ 7} and the range is R: { y ≥ 9}
<h3>
How to get the domain and range?</h3>
Here we have a square root, remember that the argument of the square root must be equal or larger than zero, so the domain is such that:
x - 7 ≥ 0.
Solving for x we get:
x ≥ 0 + 7
Then the domain is:
x ≥ 7
To get the range, we evaluate in the minimum of the domain:
f(7) = √(7 - 7) + 9 = 9
Then the range is the set of all values larger than 9, because the function is increasing.
So the range is R: y ≥ 9.
If you want to learn more about domain and range:
brainly.com/question/10197594
#SPJ1
5-3^x = -40
subtract 5 from each side to get
-3^x=-45
divide both sides by -1 to make them positive
3^x = 45
need to do the natural logarithm on both sides to remove the variable from the exponent
so ln(3^x) = ln(45)
use logarithm rule to move x out
x ln (3) = ln(45)
dive each term by ln(3) then simplify to get
ln(3)/ln(45)
so x = ln(3)/ln(45) which calculates out to 3.46497352
round off to ten thousandths is 3.4650
Answer:
The answer is d and b hope this helps!
