40 fl oz = how many cups and fl oz left over

Short Answer: arc LM = 110°
Comment
Any two angles that have their end points on the same end points as a chord and both moving away in the same direction (in this case down ) are equal. This is a fundamental fact about circles.

Equation
2x + 55 = x + 55
the only way this is going to make any sense is if x = 0. No other value is possible because it will destroy the equality.

Conclusion
Both angles = 55

But that's not what you are asked for.

What you are asked for
You want to know the measure of arc LM.
The angle connecting the center of the circle with its two arms running through the end points of the chord = the measure of arc LM

Draw a dot where the center of the circle is and call it O. Draw in <MOL
<MOL = 2* either of the 55° = 2 (<LKM) = 2 * 55 = 110° That's a property of the central angle.

The measure of arc LM = 110°

6 0

3 years ago

the table shows the number of students in grade 6-8 who went to local museum.of these between one half and three fourths packed

mojhsa [17]

The total number of students is 45 + 48 +40 = 133 students

1/2 * 133 ------ 3/4 * 133

(66.5 ; 99.75)

So we can say that b<span>etween 65 and 100 students packed their lunch</span>

4 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

$x^3y'' + 2x^2y' + 4y$

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ; $x=x_o$ is located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

$y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0$

$y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0$

The standard form of the differential equation is :

$\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0$

Thus;

$P(x) = \dfrac{2}{x}$

$Q(x) = \dfrac{4}{x^3}$

The zeros of $x,x^3$ is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x) and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = $x*\dfrac{2}{x}$

p(x) = 2

q(x) = x²Q(x)

q(x) = $x^2 * \dfrac{4}{x^3}$

q(x) = $\dfrac{4}{x}$

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic at x = 0

$Q(x) = \dfrac{4}{x^3}$ do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0

3 years ago