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Dmitry [639]
4 years ago
10

I don’t get it plz help

Mathematics
1 answer:
djyliett [7]4 years ago
8 0
This is the first 2 boxes just go in rows from side to side Hope this helped

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The quotient of 23 and u minus t
Rashid [163]
Quotient means division.. 23/u-t or written out is 23 divided by U minus T
7 0
3 years ago
Factor the perfect-square trinomial in y = (x2 + 2x + 1) − 1− 1.<br> y = (x + <br> )2 − 1 −1
dolphi86 [110]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

y = ( {x}^{2}  + 2x + 1) - 1

y =  ({x + 1})^{2} - 1

y =  ({x + 1})^{2} -  ({1})^{2}

We're done now but I have something to tell...

##############################

Hint :

{a}^{2} -  {b}^{2}  = (a + b)(a - b)

##############################

y = ( \: (x + 1)  + 1)( \: (x + 1) - 1) \\

y = (x + 2)(x)

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

4 0
3 years ago
Read 2 more answers
The scale factor is 3:1 what would y and x be ? Having a hard time trying to figure this out
Ainat [17]
\dfrac{3}{1} =  \dfrac{30}{y}

Cross multiply:
3y = 30

Divide by 3:
y = 10

Answer:  y = 10


\dfrac{3}{1} = \dfrac{x}{8}

Cross multiply:x = 24

Answer: x = 24



6 0
3 years ago
Please help me w the answer
evablogger [386]

Answer:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

\frac{()}{(x-4)(x-5)}

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ((x - 6)(x-10)). Now one has this much of the function assembled

\frac{(x-6)(x-10)}{(x-4)(x-5)}

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

6 0
3 years ago
Which one of these is the identity for addition?
Sedaia [141]

Answer:

Zero

Step-by-step explanation:

In math, an identity is a number, n, that when added to other numbers, gives the same number, n. The additive identity is always zero. This brings us to the identity property of addition, which simply states that when you add zero to any number, it equals the number itself

6 0
3 years ago
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