The area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².
<h3>What is the area of a heptagon?</h3>
Heptagon is the closed shape polygon which has 7 sides and 7 interior angles.
The area of the regular heptagon is found out using the following formula.

Here, (<em>a</em>) is the length of the heptagon.
A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. Put the value of side in the above formula,

Hence, the area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².
Learn more about the area of a heptagon here;
brainly.com/question/26271153
Answer:
Solution is x=2. sorry if this is not what you are looking for!
Step-by-step explanation:
Let , coordinate of points are P( h,k ).
Also , k = 3h + 1
Distance of P from origin :

Distance of P from ( -3, 4 ) :

Now , these distance are equal :

Solving above equation , we get :

Hence , this is the required solution.
Answer:
2.5 yards
Step-by-step explanation:
75÷30=2.5 yards
Hope this helps!
Answer:
We know that the rectangular plate has measures of:
length = 7.6 ± 0.05 cm
width = 3.1 ± 0.05 cm
(the error is 0.05cm because we know that both measures are correct to one decimal place)
First, the upper bound of the length is equal to the measure of the length plus the error, this is:
L = 7.6 cm + 0.05 cm = 7.65 cm
The upper bound of the area is the area calculated when we use the upper bound of the length and the upper bound of the widht.
Remember that the area for a rectangle of length L and width W, is:
A = W*L
Then the upper bound of the area is:
A = (7.6cm + 0.05cm)*(3.1cm + 0.05cm) = 10.8 cm^2