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3 years ago

What multiplys by 11/2 gets to15/4? please fast helpppppppp

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

5 0

Answer: 11/2 x 15/4 = 165 /8 = 205 /8 = 20.625

Step-by-step explanation:

Multiple: 11 /2 * 15 /4 = 11 · 15 2 · 4 = 165 /8

Multiply both numerators and denominators.

nikitadnepr [17]3 years ago

5 0

Answer:

11/2 x 15/4 = 165

/8 = 205

/8 = 20.625

Step-by-step explanation:

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Find the distance in units between 5/8 and 1/4 on a number line.

almond37 [142]

Answer:

3/8

Step-by-step explanation:

convert 1/4 to 2/8 and then subtract and that would equal the distance. distance of 3/8 hope this helps

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3 years ago

Find the tangents of the acute angles in the right triangle. Write each answer as a fraction,

julia-pushkina [17]

Answer:

Following are the solution to these question:

Step-by-step explanation:

Please find the complete question in the attachment file.

Formula:

$\to \tan \theta= \frac{Perpendicular}{Base}$

$\to \tan R = \frac{45}{28} \\\\ \to \tan S = \frac{28}{45}$

7 0

3 years ago

HELP ME PLEASE :(

Alina [70]

Correct option D) 1,185.6 inches cubed .

<u>Step-by-step explanation:</u>

Here we have , A triangular prism. The triangular base has a base of 12 inches and height of 10.4 inches. The height of the prism is 19 inches. We need to find the volume of the triangular prism .Let's find out:

We have following parameters :

$b=12 inches\\h=10.4inches\\l=19inhes$

We know that , Volume of triangular prism is :

⇒ $Volume = \frac{1}{2}b(h)(l)$

⇒ $Volume = \frac{1}{2}12(10.4)(19)$

⇒ $Volume = 6(10.4)(19)$

⇒ $Volume = 1,185.6in^3$

Therefore , Correct option D) 1,185.6 inches cubed .

5 0

3 years ago

Read 2 more answers

Please help me asap.

Roman55 [17]

Answer:

3. 93.48ft

Step-by-step explanation: You just multiply 11.4ft and 8.2ft!

6 0

2 years ago

Read 2 more answers

Use the normal distribution to find a confidence interval for a difference in proportions p1-p2 given the relevant sample result

9966 [12]

Answer:

a) $\hat p_1 -\hat p_2= 0.2-0.35= -0.15$

b) $ME= 2.58 \sqrt{\frac{0.2(1-0.2)}{60} +\frac{0.8(1-0.8)}{100}} =0.169$

c) $(0.2-0.35) - 2.58 \sqrt{\frac{0.2(1-0.2)}{60} +\frac{0.8(1-0.8)}{100}} =-0.319$

$(0.2-0.35) + 2.58 \sqrt{\frac{0.2(1-0.2)}{60} +\frac{0.8(1-0.8)}{100}} =0.0185$

And the 99% confidence interval would be given (-0.319;0.0185).

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_1$ represent the real population proportion 1

$\hat p_1=0.2$ represent the estimated proportion 1

$n_1=60$ is the sample size required 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.35$ represent the estimated proportion 2

$n_2=100$ is the sample size required for Brand B

$z$ represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_2)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

Part a

The best estimate is given by:

$\hat p_1 -\hat p_2= 0.2-0.35= -0.15$

Part b

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The margin of error is given by:

$ME= 2.58 \sqrt{\frac{0.2(1-0.2)}{60} +\frac{0.8(1-0.8)}{100}} =0.169$

Part c

And replacing into the confidence interval formula we got:

$(0.2-0.35) - 2.58 \sqrt{\frac{0.2(1-0.2)}{60} +\frac{0.8(1-0.8)}{100}} =-0.319$

$(0.2-0.35) + 2.58 \sqrt{\frac{0.2(1-0.2)}{60} +\frac{0.8(1-0.8)}{100}} =0.0185$

And the 99% confidence interval would be given (-0.319;0.0185).

4 0

3 years ago