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sergeinik [125]
3 years ago
7

What are the solutions to 2x^2+7x=4? Select all that apply.

Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0
<span><span><span>2<span>x2</span></span>+<span>7x</span></span>=4</span>Step 1: Subtract 4 from both sides.<span><span><span><span>2<span>x2</span></span>+<span>7x</span></span>−4</span>=<span>4−4</span></span><span><span><span><span>2<span>x2</span></span>+<span>7x</span></span>−4</span>=0</span>Step 2: Factor left side of equation.<span><span><span>(<span><span>2x</span>−1</span>)</span><span>(<span>x+4</span>)</span></span>=0</span>Step 3: Set factors equal to 0.<span><span><span><span>2x</span>−1</span>=<span><span><span>0<span> or </span></span>x</span>+4</span></span>=0</span><span><span>x=<span><span><span>12</span><span> or </span></span>x</span></span>=<span>−4</span></span>Answer:<span><span>x=<span><span><span>12</span><span> or </span></span>x</span></span>=<span>−<span>4</span></span></span>
gladu [14]3 years ago
4 0
There are two answers
1/2 and -4
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Answer:

The digit that should be placed in the blank is 0.

Step-by-step explanation:

We are given the four-digit number: 138_

And we want to determine the digit that should be placed in the blank to make the number be divisible by both 4 and 5.

A number that is divisible by 5 must end in either 0 or 5. This leaves us with only two options: 1380 or 1385.

Recalling divisibility rules, for a number to be divisible by 4, its last two digits must be divisible by 4.

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White raven [17]
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Answer:

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Hoping it helps you dear

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