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sergeinik [125]
3 years ago
7

What are the solutions to 2x^2+7x=4? Select all that apply.

Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0
<span><span><span>2<span>x2</span></span>+<span>7x</span></span>=4</span>Step 1: Subtract 4 from both sides.<span><span><span><span>2<span>x2</span></span>+<span>7x</span></span>−4</span>=<span>4−4</span></span><span><span><span><span>2<span>x2</span></span>+<span>7x</span></span>−4</span>=0</span>Step 2: Factor left side of equation.<span><span><span>(<span><span>2x</span>−1</span>)</span><span>(<span>x+4</span>)</span></span>=0</span>Step 3: Set factors equal to 0.<span><span><span><span>2x</span>−1</span>=<span><span><span>0<span> or </span></span>x</span>+4</span></span>=0</span><span><span>x=<span><span><span>12</span><span> or </span></span>x</span></span>=<span>−4</span></span>Answer:<span><span>x=<span><span><span>12</span><span> or </span></span>x</span></span>=<span>−<span>4</span></span></span>
gladu [14]3 years ago
4 0
There are two answers
1/2 and -4
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Now x=3 gives log4(0) on the left and right, which does not exist.

So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
 
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