The formula S=16t^2 is used to approximate the distance S, in feet, that an object falls freely from rest in t seconds. The heig
ht of a building is 1221 feet . How long would it take for an object to fall from the top
2 answers:
H(t)=-16t^2+1221 is the function for the height as a function of time. It will hit the ground when h=0 so:
-16t^2+1221=0
16t^2-1221=0
16t^2=1221
t^2=1221/16
t=√(1221/16) seconds
t≈8.74 seconds (to nearest hundredth of a second)
S=16t^2
1221=16t^2
1221/16=t^2
square root of 76.3=t
t=8.7
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Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10
0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes
q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters
so there are (10 - 6) = 4 more quarters then dimes
