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2 years ago

8

What will be the output of the program? public class SqrtExample { 03 03 O NaN O Compilation fails public static void main(Strin

g [] args) { double value = -9.0; System.out.println( Math ,sqrt(value));

1 answer:

Vaselesa [24]2 years ago

8 0

Answer:

216apower4 b + 512 abpower4

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Find (f*g)(x) when f(x)=x^2-7x+12 and g(x)=3/x^2-16

IgorC [24]

The answer is: $(f*g)(x)= \frac{3x-9}{x+4}$

<u><em>Explanation</em></u>

Given functions are.......

$f(x)=x^2-7x+12$

$g(x)= \frac{3}{x^2-16}$

For finding $(f*g)(x)$ , we just <u>need to multiply the two functions</u> $f(x)$ and $g(x)$ . So......

$(f*g)(x)= f(x)*g(x)\\ \\ (f*g)(x)= (x^2-7x+12)(\frac{3}{x^2-16})\\ \\ (f*g)(x)= [(x-3)(x-4)][\frac{3}{(x+4)(x-4)}]\\ \\ (f*g)(x)= \frac{3(x-3)}{x+4} = \frac{3x-9}{x+4}$

4 0

3 years ago

4 subtracted from the product of a number n multiplied by 2 is greater than or equal to 20. which of the following equations mat

Doss [256]

2n - 4 ≥ 20 is your answer

6 0

3 years ago

Simplify completely..........

vitfil [10]

Answer:

$\frac{x}{x-1}$

Step-by-step explanation:

$\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}$ $[ \ x^ 2- 1 = (x-1)(x + 1) \ ]$

$= \frac{3x^2 - 1}{(x-1)(x + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}$ $[\ Taking \ LCM \ ]$

$= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}$

<em><u>Finding LCM :</u></em>

Example :

$\frac{1}{6} + \frac{1}{3}$

6 = 2 x 3

3 = 1 x 3

$\frac{1}{2 \times 3} + \frac{1}{ 3}$ $= \frac{1}{2 \times 3} + \frac{1 \times 2}{ 3 \times 2}$

[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

$(x^2 - 1 ) = (x -1)(x+1)\\\\(x + 1) = 1 \times (x + 1)$

Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

$\frac{2x + 1}{x + 1} = \frac{(2x + 1)(x - 1)}{(x + 1)( x - 1)}$

7 0

3 years ago

Help me please. <br>20+(-16)4

Sphinxa [80]

P.E.M.D.A.S
First , you multiply.

200+(-16)4
200+(-64)

Since they have different signs, you subtract and keep the sign of the greater absolute value.

200+(-64)=136

8 0

3 years ago

Which is true of weak acids and bases?

morpeh [17]

Answer:

They partially dissocate in water ( first choice)

3 0

3 years ago