What Is 1,270 rounded to the nearest hundred?

What is the Mean in the following number sequence: 6, 14, 8, 15, 16, 13, 19

Ray Of Light [21]

Look at the attached picture ⤴

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8 0

4 years ago

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Which equation is the inverse of y = x2 – 36? y = plus-or-minus startroot x endroot 6 y = plus-or-minus startroot x 36 endroot y

svet-max [94.6K]

The inverse of the given function is expressed as y = ±√x + 38

<h3>Inverse of an equation</h3>

Given the equation below expressed as:

y = x² - 36

Replace y with x

x = y² - 38

Add 38 to both sides of the equation

x + 38 = y² - 38 + 38
y² = x + 38

Take the square root of both sides

√y² = ±√x + 38

y = ±√x + 38

Hence the inverse of the given function is expressed as y = ±√x + 38

Learn more on inverse of function here: brainly.com/question/3831584

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6 0

2 years ago

In a survey conducted by a website, employers were asked if they had ever sent an employee home because they were dressed inappr

castortr0y [4]

Answer:

$z=\frac{0.353 -0.333}{\sqrt{\frac{0.333(1-0.333)}{2759}}}=2.23$

$p_v =P(z>2.23)=0.0129$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of more than one-third of employers have sent an employee home to change clothes is higher than 1/3 or 0.333.

Step-by-step explanation:

Data given and notation

n=2759 represent the random sample taken

X=974 represent the people saying that they had sent an employee home for inappropriate attire

$\hat p=\frac{974}{2759}=0.353$ estimated proportion of people saying that they had sent an employee home for inappropriate attire

$p_o=0.333$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than one-third of employers have sent an employee home to change clothes.:

Null hypothesis: $p \leq 0.33$

Alternative hypothesis: $p > 0.33$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.353 -0.333}{\sqrt{\frac{0.333(1-0.333)}{2759}}}=2.23$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed the p value would be:

$p_v =P(z>2.23)=0.0129$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of more than one-third of employers have sent an employee home to change clothes is higher than 1/3 or 0.333.

4 0

3 years ago

Which of the following equations is equivalent to x - y = 8?

matrenka [14]

Say x = 12 and y = 4
12 - 4 = 8

Number 1
2(12) - 4(4) = 8
24 - 16 = 8
Number 1 is your Answer

4 0

4 years ago

Read 2 more answers

3 3 3 3 3 3 3 3 3 3 3 3 3 3 33

Delvig [45]

Answer: the answer is c

Step-by-step explanation: