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3 years ago

12

What Is 1,270 rounded to the nearest hundred?

1 answer:

ankoles [38]3 years ago

5 0

It would be 1,300. When rounding, you'd need to look at the number to the right of the place you're rounding to. In this case, you're rounding to the hundreds place (the 2), so you look at the number to the right (7). To know if you round up or down use this:

Round down= 0-4
Round up= 5-9

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Bruce flipped a penny 5 times. It landed on heads 2 times and tails 3 times. If he flips the coin a 6th time, which of the follo

Brums [2.3K]

Answer:

C

Step-by-step explanation:

because if the pattern were 2 on heads and three on tails the next flip would be heads

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2 years ago

For which value of x is the equation 3(3 + x) = 15 + x true?<br> A) 1 <br> B) 2 <br> C) 3 <br> D) 4

natulia [17]

Answer:

C

Step-by-step explanation:

3(3 + x) = 15 + x

Open bracket

9 + 3x = 15 + x

Collecting like terms

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x = 6/2

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3 years ago

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A square has an area of 4 square centimeters. What is the length of one side, in centimeters?

Lunna [17]

Answer:

2 cm

Step-by-step explanation:

$\sqrt{4 cm^{2}} =2 cm$

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2 years ago

What would be the ending bank balance?

JulijaS [17]

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3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

2 years ago