The answer is c hope this helps
Answer:
<h2>The function f(x) = (x - 6)(x - 6) has only one x-intercept. But at (6, 0) not at (-6, 0).</h2>
Step-by-step explanation:
The intercept form of a quadratic equation (parabola):

p, q - x-intercepts
Therefore
The function f(x) = x(x - 6) = (x - 0)(x - 6) has two x-intercepts at (0, 0) and (6, 0)
The function f(x) = (x - 6)(x - 6) has only one x-intercept at (6, 0)
The function f(x) = (x + 6)(x - 6) = (x - (-6))(x - 6)
has two x-intercept at (-6, 0) and (6, 0)
The function f(x) = (x + 1)(x + 6) = (x - (-1))(x - (-6))
has two x-intercepts at (-1, 0) and (-6, 0).
Y=2(4)+8
y=8+8
y=16
Hope this helps :)
Answer:
C
Step-by-step explanation:
Parallel and opposite sides of a parallelogram are equal. Hence, we can say:
x + 30 = 2x - 10
and
2y-10 = y +10
Solving first one, we get:
x + 30 = 2x - 10
30+10 = x
x = 40
Also
2y - 10 = y + 10
y = 10 + 10
y = 20
Now, z = x - y, so
z = 40 - 20 = 20
Answer C is right.