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horrorfan [7]
3 years ago
13

1.What is the interquartile range for the data set?

Mathematics
1 answer:
devlian [24]3 years ago
3 0
1. First, put the range in order and then divide the set into quarters. In this case, quartiles are between numbers.
<span>83, 85, 89,   l    91, 95, 104,  l   112, 118, 118,  l  125, 134, 138
Q</span>₁ = (89 + 91)/2 = 90
Q₂ = (104 + 112)/2 =108
Q₃ = (118 + 125)/2 = 121.5
Interquartile range (IQR) = Q₃ - Q₁
                                        = 121.5 - 90
                                 IQR = 31.5
2. To find the standard deviation follow the simple steps.
Formula in finding the standard deviation: (see attached file)
     Step 1. Work out the simple average of the numbers (mean)
                <span><span><u>212 + 249 + 212 + 248 + 239 + 212 + 216 + 234 + 248</u>
</span>                                                  9
              = <span><u>2070</u>
</span>                     9
mean (</span>μ) = 230
    
    Step 2. Subtract the mean on each number and square the result.
212 - 230 = (-18)² = 324<span>
249 </span>- 230 = ( 19)² = 361<span>
212 </span>- 230 = (-18)² = 324<span>
248 </span>- 230 = (18)²  = 324<span>
239 </span>- 230 = (9)²    = 81<span>
212 </span>- 230 = (-18)² =324<span>
216 </span>- 230 = (-14)² =196<span>
234 </span>- 230 = (4)²    =16<span>
248 </span>- 230 = (18)²  =324

     Step 3. Add all the squared results and get the mean.
                  <span><u>2274</u>
</span>                     9
       Variance = 252.6666667
    Step 4. Get the square root of the variance.
                  √252.6666667
                  = 15.89549202
     
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