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Andrej [43]
3 years ago
15

What's the answer to 1&2 plzz

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0
1. 2880 
2. 67%
 Its simple math just put in effort

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I’d love the answer ASAP please
Zepler [3.9K]

Answer:

1872 cm^3

Step-by-step explanation:

To solve this you can split the shape into two parts, the large rectangle with length 18 and width 8, and the small rectangle with length 6 and width 3.

So now apply the volume formula,

for the larger shape,

V = Area * height

V = L*W *H

V = 18*8*12

The volume of one part is 1728.

Now for the second shape on top,

V = L*W*H

V = 6*8*3 = 144

Now add the two, 1728+ 144 = 1872

1872 cubic centimeters

6 0
3 years ago
How do you solve for x on letter F
Nataliya [291]
Hoped this helped chu lol

8 0
3 years ago
A pharmacist receives a shipment of 21 bottles of a drug and has three of the bottles tested. If five of the 21 bottles are cont
blagie [28]

Answer:

The probability is 0.8722

Step-by-step explanation:

There are 21 bottles

5 of them are contaminated.

there are 21 - 5 = 16 non-contaminated bottles.

So, if we grab a bottle at random, the probability that this bottle is contaminated will be equal to the quotient between the number of contaminated bottles and the total number of bottles, this is:

p = 5/21

Now we want to find the probability that, for 3 tested bottles, that less than two (0 or 1 ) are contaminated.

Let's see each case on its own.

0 bottles:

The probability of getting a non-contaminated bottle in the first try is equal to the quotient between the number of non-contaminated bottles and the total number of bottles, this is:

p₁ = 16/21

For the second bottle is the same, but because one non-contaminated bottle was drawn before, now there are 15 non-contaminated bottles and 20 bottles in total, so now the probability is:

p₂ = 15/20

and similarly, for the third bottle the probability is:

p₃ = 14/19

The joint probability is the product of the individual probabilities, we get:

P = p₁*p₂*p₃ = (16/21)*(15/20)*(14/19) = 0.4211

Now the case that one bottle is contaminated.

Let's assume that the first one is contaminated.

The probability of getting a contaminated bottle in the first draw is equal to the quotient between the number of contaminated bottles and the total number of bottles, so:

p₁ = 5/21

For the second bottle, we want a non-contaminated one, there are 16 non-contaminated bottles and 20 bottles left, so here the probability is:

p₂ = 16/20

and for the third bottle we have the probability:

p₃ = 15/19

The joint probability is:

p = p₁*p₂*p₃ = (5/21)*(16/20)*(15/19)

Also notice that we only looked at the case where the first bottle is contaminated, we also have the case where the second one is contaminated and the case where the third one is  contaminated, so there are 3 permutations, then the probability of having one contaminated bottle is:

Q = 3*p = 3*(5/21)*(16/20)*(15/19) = 0.4511

Then the probability of having less than two contaminated bottles is:

probability = P + Q = 0.4211 + 0.4511 = 0.8722

8 0
3 years ago
Yesterday, Joe had $376 in his bank account. Today, Joe noticed his account had a balance of -$523. Joe realized that he spent m
Phantasy [73]
Joe overspent D. $899
7 0
3 years ago
What’s 1 plus 1 please hurrt
Aleks04 [339]
1+1 is equal to 2 lol
5 0
3 years ago
Read 2 more answers
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