The greatest number can be as large as 81.
<u>Step-by-step explanation:</u>
Given that,
- A set of five different positive integers has a mean of 33 and a median of 40.
- We need to find the set of five different positive integers.
We already know that,
- The term "median" is the middle term which is 40.
- Therefore, if you do not include 0 in positive integers, then the first two positive integers below the median value of 40 to be as low as possible are 1 and 2.
- The median 40 will be the third positive integer of the set.
- Therefore, the fourth positive integer should be the next lowest possible value of 40 which is 41.
With simple algebra you can figure out the last greater number.
-
The set of five different positive integers is given as {1,2,40,41,x}.
- Let, x be the last greater number in the set.
The term "mean" is defined as the sum of all the integers in the set divided by the number of integers in the set.
⇒ Mean = (1+2+40+41+x) / 5
⇒ 33 = (84+x) / 5
⇒ 33×5 = 84 + x
⇒ 165 - 84 = x
⇒ 81 = x
∴ The greatest number can be as large as 81.
C is the answer hopenyou passed!!
Answer:
The complete graph of 
is shown below.
Step-by-step explanation:
Considering the function
The graph of the piece 
indicates the blue line, starting at x=3. And with one unit increase in x, the value of y decreases by 2 units.
For example,
at x = 3
and
at x = 4
By comparing the slope intercept form
Here,
The slope of which is m = -2,
and the piece 
indicates the yellow line.
By comparing the slope intercept form
Here,
- The slope of which is m = -1/3, and
The complete graph of is shown below.
Not a triangle because the two smaller numbers do not add up to a bigger number than 15
Answer:
NaNx10^-8
Step-by-step explanation:
