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2 years ago

Whats 50 times 40 ??????????

Mathematics

2 answers:

Olenka [21]2 years ago

4 0

2000, because I need 20 characters

Drupady [299]2 years ago

3 0

Answer: 2,000 yeahhhhhhhhhhhhhhhhh

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What are the smallest and largest possible numbers in base 3?

adelina 88 [10]

Our number system is in base 10. The ones place holds digits 0 - 9. When you reach 10, you must add another place value (the tens place).

Base 3 is digits 0-2 becasue when you reach 3, you need to add another place value.

Therefore, the smallest number is 0 and the largest number is 2.

Answer: smallest = 0, largest = 2

3 0

3 years ago

Can this be reduced?

Andre45 [30]

This answer is 2/11
I used my brain lol !!!

5 0

2 years ago

Read 2 more answers

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

2 years ago

Looking for more friends(whats 2+2)<br> plz dont report

JulsSmile [24]

Answer:

Step-by-step explanation:

thz for the point :)))))))))))

6 0

2 years ago

Read 2 more answers

Please help guys this khan and litteraly have this unit test please guys illl mark brainliest

tankabanditka [31]

Answer:

x=36

Step-by-step explanation:

So, lets go over what we know:

16 is equal to 4/9ths of x.

As a equation, this looks like:

$16 = \frac{4}{9}x$

We can begin to solve for x by multiplying both sides by the denominator, 9, which gets us:

$16*9 = 4x$

$144 = 4x$

Then we can divide by the coefficent of x, which is 4, to get our answer:

$\frac{144}{4} = x$

$36=x$

This is our answer! Hope this helps! :3

6 0

1 year ago

Read 2 more answers