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3 years ago

Apply the distributive property to factor out the greatest common factor. {16g + 20h} =16g+20h=

Mathematics

1 answer:

vladimir1956 [14]3 years ago

5 0

Answer:

Step-by-step explanation:

16g = 2 * 2 * 2 * 2 * g

20h = 2 * 2 * 5 * h

Greatest common factor = 2 * 2 = 4

16g + 20h = (4*4*g)+(4*5*h)

= 4(4g + 5h)

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Which expression is equivalent to

pychu [463]

Answer:

Step-by-step explanation:

i cannot find an answer from the expression but i can guess if you didnt follow pemdas, it would be d

3.5 × 102 is 357

(8 × 10−4) + (6 × 10−4) is 132

132/357= .369 or .37 or 0 simplified

d is 4*10-10

10-10 is 0

4*0 is 0

8 0

2 years ago

Sum of integers from 15 to 25 inclusive

Fofino [41]

−
138
Explanation:
The only perfect squares between 15 and 25 inclusive are
16
and
25
∴
Sum of perfect squares
=
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1 year ago

PLEASE ANSWER THIS :(

PolarNik [594]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In Sweden, 10 people are struck by lightning every year, on average. Answer thefollowing questions about a given year in Sweden

emmainna [20.7K]

Answer:

a) 19.85% probability that a total of two people are struck by lightning during first four months of the year.

b) 22.68% probability that the year has 5 good and 7 bad months

Step-by-step explanation:

We are going to use the Poisson distribution and the binomial distribition to solve this question.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a.Find the probability that a total of two people are struck by lightning during first four months of the year.

10 people during a year(12 months).

In 4 months, the mean is $\mu = \frac{10*4}{12} = 3.33$

This is P(X = 2).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-3.33}*(3.33)^{2}}{(2)!} = 0.1985$

19.85% probability that a total of two people are struck by lightning during first four months of the year.

b.Say that a month is good is no one is struck by lightning, and bad otherwise. Find the probability that the year has 5 good and 7 bad months.

Probability that a month is good.

P(X = 0), Poisson

The mean is $\mu = \frac{10*1}{12} = 0.8333$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.8333}*(0.8333)^{0}}{(0)!} = 0.4346$

Find the probability that the year has 5 good and 7 bad months.

Now we use the binomial distribution, we want P(X = 5) when n = 12, p = 0.4346. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{12,5}.(0.4346)^{5}.(0.5654)^{7} = 0.2268$

22.68% probability that the year has 5 good and 7 bad months

3 0

3 years ago

Find the domain of the function

densk [106]

Answer:

3x - 7 ≥ 0

3x ≥ 7

x ≥ 7/3

D = [7/3 ; ∞[

D = [7/3 ; ∞)

4 0

2 years ago