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uranmaximum [27]
4 years ago
12

The roots of a given function are 4i and 8. how many total roots are there?

Mathematics
1 answer:
k0ka [10]4 years ago
5 0
The presence of an imaginary root (such as 4i) requires the presence of the complement of that root (which is -4i).  Thus, there are 3 roots total here.
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HELP DUE LIKE RIGHT NOW​
Nimfa-mama [501]

Answer:

The correct answer is x = 17.

Step-by-step explanation:

If EF bisects DEG, this means that angles DEF and angles FEG are congruent, and they each make up half of angle DEG.

Therefore, we can set up the equation:

DEF + FEG = DEG

However, since we know that DEF and FEG represent the same value, we can change this equation into the following:

2(DEF) = DEG

Now, we can substitute in the expressions that we are given:

2(3x+1) = 5x + 19

To simplify, we should first use the distributive property on the left side of the equation.

6x + 2 = 5x + 19

Our next step is to subtract 5x from both sides of the equation.

x + 2 = 19

Finally, we can subtract 2 from both sides of the equation to get x by itself on the left side.

x = 17

Therefore, the value of x is 17.

Hope this helps!

7 0
4 years ago
Please help me finish this part of my study guide
Mazyrski [523]

Answer:

(5,15)

Step-by-step explanation:

We know that 225 = 15a + 10c, and he purchased a total of 20 tickets, so

a + c = 20, using this, we know that c = 20 - a, we can substitute this for c in 225 = 15a + 10c to get:

225 = 15a + 10(20 - a) =

225 = 15a + 200 - 10a

225 = 5a + 200

25 = 5a

a = 5

Now we substitute 5 for a:

225 = 15a + 10c

225 = 15(5) + 10c

225 = 75 + 10c

150 = 10c

c = 15

so a = 5 and c = 15, the solution is (5,15)

P.S. I'm the guy who did your other question

4 0
3 years ago
Read 2 more answers
Scientific notation<br> how do I do this? ​
DENIUS [597]

Answer:

Post the questions and I'll do my best to help

Step-by-step explanation:

6 0
3 years ago
Please help!
Gemiola [76]

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

In this exercise we must apply the definition of derivative, which is described below:

f'(x) =  \lim_{x \to 0} a_n \frac{f(x+h)-f(x)}{h} (1)

If we know that f(x) = 2\cdot x^{2}-9, then the derivative of the expression is:

f'(x) =  \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}

f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}

f'(x) = 2\cdot  \lim_{h \to 0} 2\cdot x + h

f'(x) = 4\cdot x

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

We kindly invite to check this question on derivatives: brainly.com/question/23847661

4 0
3 years ago
Is the derivative of square root of 6x, 3x^(-1/2)?
strojnjashka [21]
Lets calculate derivative of \sqrt{6x}

That is:
( 6x^{ \frac{1}{2} } )' = 6* \frac{1}{2} * x^{ \frac{1}{2}  -1 } = 3* x^{- \frac{1}{2} }

Comparing that with offered answer we can see that results match.
6 0
3 years ago
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