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3 years ago

Describe possible dimensions of a pyramid with a volume of 30 cubic centimeters.

Mathematics

2 answers:

Archy [21]3 years ago

8 0

Answer:

15*3*2

15*1*6

45*2*1

10*3*3

6*5*3

Step-by-step explanation:

Volume=Lenth *Width*Height divieded by 3

Contact [7]3 years ago

4 0

Answer:

15*3*2

15*1*6

45*2*1

10*3*3

6*5*3

Step-by-step explanation:

Volume=Lenth *Width*Height divieded by 3

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Find the range of y= 3/2 cos 4x-1

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I have attached how to work through this problem. I hope this helps

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3 years ago

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Ella is Bono motorcycle and he’s taking out a loan in the amount of $15,000 her choice is for the loan or a 36 month loan at 6.5

klemol [59]

Answer:

Step-by-step explanation:

Step-by-step explanation:

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

Considering the 36-month loan,

T = 36 months = 36/12 = 3 years

P = $15000

R = 6.5%

Therefore

I = (15000 × 6.5 × 3)/100

I = 292500/100

I = $2925

Considering the 48-month loan loan,

T = 48 months = 48/12 = 4 years

P = $15000

R = 7.5%

Therefore

I = (15000 × 7.5 × 4)/100

I = 450000/100

I = $4500

The difference in the amount of interest Ella would have to pay for these two loans is

4500 - 2925 = $1575

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2 years ago

If you add 1 to half of 1, then half of 1 to the previous number, and so on, will you ever get to 2?

lisov135 [29]

Answer:

Step-by-step explanation:

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3 years ago

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Please help it's due tmrw

Makovka662 [10]

Answer:

If you just use you finger to keep track of one point and follow each set of instructions you will find that B is correct.

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3 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

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3 years ago