Given:
and
, AE = BF, and ED = FC.
We prove that AD = BC as follows:
Statement Reason
1.
and
Given
2. AE + ED = AD Segment Addition Postulate
BF + FC = BC
3. AE = BF and ED = FC Given
4. BF + FC = AD Substitution
5. AD = BC Transitivity property
I need this answer too can someone please help us out with the right answer?!
Explanation:
Answer:
56/132
Step-by-step explanation:
First round: 8/12
Second round: 7/11, because you can't have the same boy twice.
Multiply them together to get 56/132
Answer:
9 Superscript negative 3
Step-by-step explanation:
In gcd we only take common number and unless there is no common number present, it won't change