Sum f(k)=4k-10 for k=1 to 18.
We sum each term separately and add the sums.
![\sum_1^{18}4k=4\sum_1^{18}k=4[18(1+18)/2]=4*9*19=684](https://tex.z-dn.net/?f=%5Csum_1%5E%7B18%7D4k%3D4%5Csum_1%5E%7B18%7Dk%3D4%5B18%281%2B18%29%2F2%5D%3D4%2A9%2A19%3D684)
Therefore the required sum is 684-180=504
Answer:
$13200
Step-by-step explanation:
All we have to do is set up a proportion.
1200/100=x/1100
Thathat means that
100x=1,320,000
x= 13200
Answer four hundred and twenty
<span><u>How many grams in a kilogram you ask? Kilograms and grams (kg to g) mass units conversion factor are 1000. To find out how many grams in kilograms, multiply the kilogram value by 1000 or use the converter.</u>
If you need more help I will be glad to help!:D
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You would combine like this:
17e=18
Then divide off the sides
17e/17e 18/17e which cross out the 17 e which leaves you with 1.1
