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3 years ago

A light bulb consumes 2400 watt-hours per day. how long does it take to consume 9000 watt- hours?

Mathematics

1 answer:

Luden [163]3 years ago

8 0

Answer:

3.75

Step-by-step explanation:

Set up the following ratio:

2400 watt-hours 1 day

------------------------- = ----------

9000 watt-hours x days

Then do criss-cross-apple-sauce:

x*2400=9000*1

And then solve for x:

2400x=9000

x=9000/2400

x=3.75

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3 years ago

The expresion 14.42d + 12.24c can be used to find the total cost of d punds of almonds and c pounds of cashews how much does it

madam [21]

Answer:

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

$y=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in $]

Step-by-step explanation:

[The unit of price is not given, I assume the unit of cost as $]

Given expression is 14.42 d + 12.24 c .

Where the amount of almond is denoted by d pounds.

and the amount of cashews is denoted by c pounds.

The cost price of d pound of almond is $14.42.

The cost price of 1 pound of almond is $\$\frac{14.42}{d}$

Then the cost of $3\frac{1}{2}$ pound of almond is $=\$\frac{ 14.42 \times3 \frac{1}{2} }{d}$

$=\$\frac{36.05}{d}$

Again from the given expression we get that,

The cost price of c pound of cashews is $12.24

The cost price of 1 pound of cashews is $=\$\frac{12.24}{c}$

Then the cost of $3\frac{1}{2}$ pound of cashews is $=\$\frac{ 12.24 \times3 \frac{1}{2} }{c}$

$=\$\frac{30.6}{c}$

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

y = $=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in$]

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