<span>Here, we first calculate the value of 't' and then go on calculating the probability that the t-value is more than calculated t-value, given the degree of freedom (d.f. = n-1).
t.calc = (77-76)/(5/sqrt(100)) = 1/(1/2) = 2
P(x > 77) = P(t > 2, d.f. =99) = 0.0241= 2.41%</span>
£26.4 because 10÷3 is 3.3 requiring and 3.3×8 is 26.4
Answer:
7788
Step-by-step explanation:
177 x 44 is 7788
Is there more to this problem?